x^2+5x-6=2x^2+2x-10

Solution for x^2+5x-6=2x^2+2x-10 equation:

x^2+5x-6=2x^2+2x-10

We move all terms to the left:

x^2+5x-6-(2x^2+2x-10)=0

We get rid of parentheses

x^2-2x^2+5x-2x+10-6=0

We add all the numbers together, and all the variables

-1x^2+3x+4=0

a = -1; b = 3; c = +4;
Δ = b2-4ac
Δ = 32-4·(-1)·4
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-5}{2*-1}=\frac{-8}{-2}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+5}{2*-1}=\frac{2}{-2}
=-1
$